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(7)=-E^2-9E
We move all terms to the left:
(7)-(-E^2-9E)=0
We get rid of parentheses
E^2+9E+7=0
a = 1; b = 9; c = +7;
Δ = b2-4ac
Δ = 92-4·1·7
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{53}}{2*1}=\frac{-9-\sqrt{53}}{2} $$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{53}}{2*1}=\frac{-9+\sqrt{53}}{2} $
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